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9m^2-24m=2
We move all terms to the left:
9m^2-24m-(2)=0
a = 9; b = -24; c = -2;
Δ = b2-4ac
Δ = -242-4·9·(-2)
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-18\sqrt{2}}{2*9}=\frac{24-18\sqrt{2}}{18} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+18\sqrt{2}}{2*9}=\frac{24+18\sqrt{2}}{18} $
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